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[DhtmlXQ_adddate]2013-11-03 14:14:01[/DhtmlXQ_adddate]
[DhtmlXQ_editdate]2013-11-03 14:14:00[/DhtmlXQ_editdate]
[DhtmlXQ_title]《弃子十三刀100例》2[/DhtmlXQ_title]
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[DhtmlXQ_comment0]通过分析可以看出，红方的两个车如果没有，杀起来反倒简单。只需兵三平四再后炮平四就结束战斗了。因此，弃掉这两个车，为后炮平肋让路，就成为理所当然的思路。着法如下（红先胜）：[/DhtmlXQ_comment0]
[DhtmlXQ_comment5] 第一次弃子让路，弃掉此车意在为后炮平四从纵线攻击做准备）[/DhtmlXQ_comment5]
[DhtmlXQ_comment9] ！（第二次弃子让路，作用与前同）[/DhtmlXQ_comment9]
[DhtmlXQ_comment11] 此局也是两次使用弃子让路战术的范例。值得注意的是，在先后次序上，必须先弃八路车。如先弃掉五路车，再车八进二打将准备弃子时，黑可退士化解。而先走车八进二打将时，黑不能退士，否则红车五平四即胜。[/DhtmlXQ_comment11]
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